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8x^2+10x-280=0
a = 8; b = 10; c = -280;
Δ = b2-4ac
Δ = 102-4·8·(-280)
Δ = 9060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9060}=\sqrt{4*2265}=\sqrt{4}*\sqrt{2265}=2\sqrt{2265}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{2265}}{2*8}=\frac{-10-2\sqrt{2265}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{2265}}{2*8}=\frac{-10+2\sqrt{2265}}{16} $
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